Question

x2＋y2=x 则u=3x2＋0.5y2的值域为.

Answer 1

x2＋y2=x

Y^2=X-X^2

u=3x2＋0.5y2=3X^2+0.5(X-X^2)=2.5X^2+0.5X

函数的对称轴为 X=-0.5/5=-0.1

又Y^2>=0 所以X-X^2>=0 即 0