函数y=(x^2+2)/(x-1) (x>1)的最

函数y=(x^2+2)/(x-1) (x>1)的最小值

2个回答

y=[(x-1)(x+1)+3]/(x-1)
这里变成y=(x-1)(x+1)/(x-1) +3/(x-1)
=x+1+3/(x-1)
=（x-1）+3/(x-1)+2