【x+y】【x-y】+【x-y】²-【x²-3xy】,其中x=2,y=1/2
2个回答
原式=x^2-y^2+x^2-2xy+y^2-x^2+3xy
=x^2+xy
=4+1=5
相关问题
x²-y²/x²+2xy+y² 减 x+y/x-y ,其中x=1 ,y=-3 【
5x²y-[2x²y-3(xy²-2x²y+2xy²)],其中x,y满
(2x^2y-2xy^2)-[(-3x^2y^2+3x^2y)+(3x^2y^2-3xy^2)]其中x=-1,y=2
[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2
-(x2+y2)+[-3xy-(x2-y2)],其中x =-1,y =2.
(3x2y-2xy2)-(xy2-2x2y),其中x=-1,y=2.
xy(y+y²)-y²(xy-x)+2x(x²-y²),其中x=二分之一,y=2
求(x+3y-3xy)-2(-2x-y+xy)的值,其中x+y=1/3,xy= -1/2
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3