x²/(y-x)+y²/(x-y)
=x²/(y-x)-y²/(y-x)
=(x²-y²)/(y-x)
=[(x+y)(x-y)]/(y-x)
=-(x+y)
=-x-y
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x²/(y-x)+y²/(x-y)
=x²/(y-x)-y²/(y-x)
=(x²-y²)/(y-x)
=[(x+y)(x-y)]/(y-x)
=-(x+y)
=-x-y
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮,