Question

sin(lnx)原函数

Answer 1

∫ sin(lnx)dx

=xsin(lnx) -∫ cos(lnx) dx

=xsin(lnx) -xcos(lnx) - ∫ sin(lnx) dx

2 ∫ sin(lnx)dx =xsin(lnx) -xcos(lnx)

∫ sin(lnx)dx = (1/2)[xsin(lnx) -xcos(lnx)] + C