Question

分式与分式方程的一道数学题不会做，求解

Answer 1

解原式

=[(a+b)/ab]^2÷(a^2-b^2)/ab

=(a+b)^2/(ab)^2×ab/(a^2-b^2)

=(a+b)^2/(ab)×1/(a+b)(a-b)

=(a+b)/(ab)×1/(a-b)

=(a+b)(a-b)/ab

=(a^2-b^2)/a