Question

是关与三角涵数的,一个三角形,直角边a与斜边b夹角为10度,直角边长7.5,求斜边b和另一斜边c长

Answer 1

c是直角边,a=7.5,是吧

tan10° = c/a

∴ c = a*tan10° = 7.5 * tan10° ≈ 1.32

cos10° = a/b

b = a / cos10° ≈ 7.62