Question

解分式方程：【（x-y分之1）-（x+y分之1）】·【（y+1)²-(y-1)²】分之【x²

Answer 1

[(x-y)分之1-(x+y)分之1]·[(y+1)²-(y-1)²]分之(x²-2xy+y²)

=[(x+y)(x-y)]分之[(x+y)-(x-y)]·[(y+1-y+1)(y+1+y-1)]分之(x-y)²

=[(x+y)(x-y)]分之(2y)·(2y)分之(x-y)²

=(x+y)分之(x-y)