先请阅读下列题目和解答过程:“已知a、b、c为△ABC的三边,且满足a 2 c 2 -b 2 c 2 =a 4 -b 4

1个回答

  • (1)从第②步到第③步出错(写成第“2”或“二”等数字都不扣分;另外直接写“第③步”

    或“到第③步”都算正确),(2分)

    (2)等号两边不能同除a 2-b 2,因为它有可能为零.(4分)

    (3)(从头或直接从第③步写解答过程都行),

    ∵a 2c 2-b 2c 2=a 4-b 4

    ∴c 2(a 2-b 2)=(a 2+b 2)(a 2-b 2),

    移项得:c 2(a 2-b 2)-(a 2+b 2)(a 2-b 2)=0,

    得(a 2-b 2)(c 2-a 2-b 2)=0,(5分)

    ∴a 2=b 2或c 2=a 2+b 2(6分)

    ∴△ABC是直角三角形或等腰三角形.(7分)