[(x+2)/(x²-2x)-(x-1)/(x²-4x+4)]÷[(x-4)/x]是这个式子吗?下面按这个式子来化简.
[(x+2)/(x²-2x)-(x-1)/(x²-4x+4)]÷[(x-4)/x]
=[(x+2)/x(x-2)-(x-1)/(x-2)²]÷[(x-4)/x]
=[(x²-4)-(x²-x)]/[x(x-2)²]÷[(x-4)/x]
=(x-4)/[x(x-2)²]*[x/(x-4)]
=1/(x-2)²
解方程(x+2÷(x平方-2x)-(x-1÷(x平方-4x+4)÷x-4÷x