z=-x-y,代入得x^2/(2x^2-xy-y^)+y^2/(2y^2-xy-x^)+(x+y)^2/(2X^2+5xy+2y^2),分母进行多项式因式分解前两项进行通分进行加法计算有
(x-y)(x^2+3xy+y^2)/[(x-y)(2x+y)(x+2y)]+(x+y)^2/[(2x+y)(x+2y)]
最后化简为1
已知x+y+z=0,求x^2/(2x^2+yz)+y^2/(2y^2+zx)+z^2/(2z^2+xy)的值
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