根号下x+3y+1 + 绝对值2x-y-5 =0
可得方程x+3y+1 =0(1)
2x-y-5 =0(2)
由(2)×3+(1),得
x+3y+1+6x-3y-15 =0
解得7x=14 x=2
把x=2带入(1),得
2+3y+1=0
解得3y=-3 y=-1
根号下x+3y+1 + 绝对值2x-y-5 =0
可得方程x+3y+1 =0(1)
2x-y-5 =0(2)
由(2)×3+(1),得
x+3y+1+6x-3y-15 =0
解得7x=14 x=2
把x=2带入(1),得
2+3y+1=0
解得3y=-3 y=-1