（1）因为｛bn｝是等比数列,b1=1,b4=54 所以2q^3=54,q=3,所以bn=2*3^n-1
（2）由（1）得,b2=6,b3=18,所以a1+a2+a3=3a1+3d=24,所以d=6,所以an=6n-4,所以an的前n项和Sn=n（3n-1）,所以S10=290.
不懂追问哦~
已知数列an是等差数列,（bn）是等比数,且a1=b1=2,b4=54,a1+a2+a3=b2+b3,求（1）数列（bn
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