(x-2y)的2次方 |y +2|=0,
即
x-2y=0,y+2=0
y=-2
x=2y=-4
所以
((x-y)的二次方 +(y+ x)(y-x))除于2y
=(x²-2xy+y²+y²-x²)÷2y
=(2y²-2xy)÷2y
=y-x
=-2+4
=2
(x-2y)的2次方 |y +2|=0,
即
x-2y=0,y+2=0
y=-2
x=2y=-4
所以
((x-y)的二次方 +(y+ x)(y-x))除于2y
=(x²-2xy+y²+y²-x²)÷2y
=(2y²-2xy)÷2y
=y-x
=-2+4
=2