(2014x)²-2013*2015x-1
=(2014²x+1)(x-1)
方法
设2014²=a
2013*2015=(2014-1)(2014+1)=a-1
所以
原式=ax²-(a-1)x-1
=(ax²-ax)+(x-1)
=ax(x-1)+(x-1)
=(ax+1)(x-1)
=(2014²x+1)(x-1)
(2014x)²-2013*2015x-1
(2014x)²-2013*2015x-1
=(2014²x+1)(x-1)
方法
设2014²=a
2013*2015=(2014-1)(2014+1)=a-1
所以
原式=ax²-(a-1)x-1
=(ax²-ax)+(x-1)
=ax(x-1)+(x-1)
=(ax+1)(x-1)
=(2014²x+1)(x-1)