Question

计算题 (1)－x²·﹙－x﹚² (2)﹙x－2﹚﹙x＋3﹚

Answer 1

1.计算题

(1)－x²·﹙－x﹚²=-x^4

(2)﹙x－2﹚﹙x＋3﹚ = x²+x-6

(3)﹙a－2b＋3c﹚﹙a＋2b－3c﹚

=a² -(2b-3c)²

=a²-4b²+12bc-9c²

﹙4﹚﹙a＋1/2﹚²·﹙a²＋1/4﹚²·﹙a－1/2﹚²

=﹙a²-1/4﹚²·﹙a²＋1/4﹚²

=﹙a^4－1/16﹚²

=a^8-1/8a^4-1/256

2.若x²＋2x＋y²－6y＋10＝0,

则（x+1)²+(y-3)²=0

x+1=0 x=-1

y-3=0 y=3