n(HCl)=0.045*0.1=0.0045mol n(NaOH)= 0.5*0.005=0.0025mol
HCl + NaOH ==== NaCl + H2O
1mol 1mol
0.0045mol 0.0025mol
HCl过量,0.0045-0.0025=0.002mol
C(H+)=0.002/0.5=0.004=4*10^-3
PH=-lg(H+)=-lg(4*10^-3)=3-lg4
n(HCl)=0.045*0.1=0.0045mol n(NaOH)= 0.5*0.005=0.0025mol
HCl + NaOH ==== NaCl + H2O
1mol 1mol
0.0045mol 0.0025mol
HCl过量,0.0045-0.0025=0.002mol
C(H+)=0.002/0.5=0.004=4*10^-3
PH=-lg(H+)=-lg(4*10^-3)=3-lg4