{3a1x+2b1y=5c1,3a2x+2b2y=5c2 两边都初以5
{3/5a1x+2/5b1y=c1,3/5a2x+2/5b2y=c2
而一中 {a1x+b1y=c1,a2x+b2y=c2
所以3/5a1x=a1x 2/5b1y=b1y(方程两边X,Y的解都不同)
因为{x=3,y=4
所以3/5X=3 X=5
2/5Y=4 ...
{3a1x+2b1y=5c1,3a2x+2b2y=5c2 两边都初以5
{3/5a1x+2/5b1y=c1,3/5a2x+2/5b2y=c2
而一中 {a1x+b1y=c1,a2x+b2y=c2
所以3/5a1x=a1x 2/5b1y=b1y(方程两边X,Y的解都不同)
因为{x=3,y=4
所以3/5X=3 X=5
2/5Y=4 ...