网上搜索的答案,
2+3+4+……+n=(n+2)(n-1)/2
∴1/(2+3+4+……+n)=2/(n+2)(n-1)=(2/3)[(1/n-1)-(1/n+2)]
∴原式=(2/3)(1/1-1/4+1/2-1/5+……+1/199-1/202)
=(2/3)(1+1/2+1/3-1/200-1/201-1/202)
=15008602/12180600
网上搜索的答案,
2+3+4+……+n=(n+2)(n-1)/2
∴1/(2+3+4+……+n)=2/(n+2)(n-1)=(2/3)[(1/n-1)-(1/n+2)]
∴原式=(2/3)(1/1-1/4+1/2-1/5+……+1/199-1/202)
=(2/3)(1+1/2+1/3-1/200-1/201-1/202)
=15008602/12180600