Question

实数x,y满足x^2+y^2-2根号下3x-2y+3=0,则y/x的最大值为

Answer 1

x^2+y^2-2√3x-2y+3=0y=kx(1+k^2)x^2-2(√3+k)x+3=0[2(√3+k)]^2-12(1+k^2)>=03+2√3k+k^2-3-3k^2>=0-2k^2+2√3k>=0k(k-√3)