lim(1/x²-cot²x)

2个回答

  • 1/x²-cot²x

    =(1-x²cot²x)/x²

    =(sin²x-x²cos²x)/(x²sin²x)

    =(sin²x-x²cos²x)/x^4

    0/0洛必达

    =(2sinxcosx-2xcos²x+2x²sinxcosx)/(4x^3)

    =[(1+x²)sin2x-2xcos²x]/(4x^3)

    0/0洛必达

    =[2xsin2x+(1+x²)2cos2x-2cos²x+4xsinxcosx]/(12x^2)

    =[4xsin2x-2cos²x+2(1+x²)cos2x]/(12x^2)

    =[4sin2x+8xcos2x+4sinxcosx+4xcos2x-4(1+x^2)sin2x]/(24x)

    =[(2-4x^2)sin2x+12xcos2x]/(24x)

    0/0洛必达

    =[-8xsin2x+2(2-4x^2)cos2x+12cos2x-24xsin2x]/24

    =16/24

    =2/3