(√6+4√3+3√2)/[(√6+√3)(√3+√2)]= (√6+√3+3√3+3√2)/[(√6+√3)(√3+√2)]=1/(√3+√2)+3/(√6+√3)=√3-√2+(√6-√3)=√6-√2(做这样的题要先观察题的特点,想方法把分母约分掉一部分,然后分母有理化,最后化简求值)
(√6+4√3+3√2)/[(√6+√3)(√3+√2)]= (√6+√3+3√3+3√2)/[(√6+√3)(√3+√2)]=1/(√3+√2)+3/(√6+√3)=√3-√2+(√6-√3)=√6-√2(做这样的题要先观察题的特点,想方法把分母约分掉一部分,然后分母有理化,最后化简求值)