(n + 1)/[4n²(n+2)²] = 1/1

(n + 1)/[4n²(n+2)²] = 1/16 * [ 1/n² - 1/(n +

2个回答

求 2^4n+1-(4^2n-1+16^n) 的值
1\n(n+1)+1\(n+1)(n+2)+1\(n+2)(n+3)+1\(n+3)(n+4)
1\n(n-2)+1\(n-2)(n-4)••••••+1\(n-(n-3))(n-(n-1))=9\20,n=____
化简：2^4n+1-(4^2n+16^n)
1-4+9-16+…+（-1）n+1n2等于（　　）
1-4+9-16+…+（-1）n+1n2等于（　　）
(n+1)(n+2)/1 +(n+2)(n+3)/1 +(n+3)(n+4)/1
n→∞ lim[1+1/(1+2n)+1/(2+2n)+1/(3+2n)+1/(4+2n).+1/(n+2n)]=
若n为正整数,求1/n(n+1)+1/(n+1)(n+2)＋1/(n+2)(n+3)+1/(n+3)(n+4)+.+1/
a1=1/4 ,a(n)=a(n-1)/{[(-1)^n]×a(n-1)-2} (n≥2,n∈N)