3x²-2(3k+1)x+3k²-1=0
方程有实根,判别式△≥0
[-2(3k+1)]²-4×3×(3k²-1)≥0
24k+16≥0
k≥-2/3
设两根分别为x1,x2,由韦达定理得
x1+x2=2(3k+1)/3
x1x2=(3k²-1)/3
两根均为负,则x1+x20
2(3k+1)/3√3/3或k
3x²-2(3k+1)x+3k²-1=0
方程有实根,判别式△≥0
[-2(3k+1)]²-4×3×(3k²-1)≥0
24k+16≥0
k≥-2/3
设两根分别为x1,x2,由韦达定理得
x1+x2=2(3k+1)/3
x1x2=(3k²-1)/3
两根均为负,则x1+x20
2(3k+1)/3√3/3或k