Question

化简代数式(2a-b)^2-(-a-1-b)(-a+b-1)+(a+1)^2,其中a=1/2,b=-2=.=不知道哪里不

Answer 1

(2a-b)^2-(-a-1-b)(-a+b-1)+(a+1)^2

=4a^2-4ab+b^2-[(-a-1)^2-b^2]+(a+1)^2

=4a^2-4ab+b^2-(a+1)^2+b^2+(a+1)^2

=4a^2-4ab+2b^2

=4*1/4-4*1/2*(-2)+2*4

=1+4+8

=13