Question

化简a/(a-b)(a-c)+b/(b-c)(b-a)+c/(c-a)(c-b)的结果是

Answer 1

a/(a-b)(a-c)+b/(b-a)(b-c)+c/(c-a)(c-b)

=a/(a-b)(a-c)-b/(a-b)(b-c)+c/(a-c)(b-c)

=[a(b-c)-b(a-c)+c(a-b)]/[(a-b)(a-c)(b-c)]

=[ab-ac-ab+bc+ac-bc]/[(a-b)(a-c)(b-c)]

=0