解f(x)=|lgx|
知f^2(5)十f(1/2)xf(50)
=|lg5|^2十|lg1/2|x|lg50|
=(lg5)^2-lg1/2xlg50
=(lg5)^2+lg2xlg50
=(lg5)^2+lg2xlg(2×25)
=(lg5)^2+lg2x(lg2+lg25)
=(lg5)^2+lg2x(lg2+2lg5)
=(lg5)^2+2lg2xlg5+(lg2)^2
=(lg5+lg2)^2
=(lg10)^2
=1^2
=1
解f(x)=|lgx|
知f^2(5)十f(1/2)xf(50)
=|lg5|^2十|lg1/2|x|lg50|
=(lg5)^2-lg1/2xlg50
=(lg5)^2+lg2xlg50
=(lg5)^2+lg2xlg(2×25)
=(lg5)^2+lg2x(lg2+lg25)
=(lg5)^2+lg2x(lg2+2lg5)
=(lg5)^2+2lg2xlg5+(lg2)^2
=(lg5+lg2)^2
=(lg10)^2
=1^2
=1