怎么把x²-xy+y²分之x²+2xy-3y³因式分解啊,
2个回答
再改一下吧
x²- 2 xy+y²分之x²+2xy-3y²
=(x+3y)(x-y)/(x-y)²
=(x+3y)/(x-y)
相关问题
若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?
若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?
y²分之(x²-2xy+y²)除以xy分之(y²-xy)乘xy²,其中x=4,y=3.
求x-xy+y分之3x+xy+3y 其中xy分之x+y=3
已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=
(3x²y-xy²)-3(x²y-2xy²) x=2分之1 y=3分之1
计算:2x+2y分之3y + x²+xy分之2xy
2x+2y分之3y 加 x²+xy分之2xy
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
已知y分之x=3,求x²-xy+y²分之x²+2xy-3y²