Question

x y m 为实数,且√（x-2m-y）+√(x-4) =√(x+y-6)+√(6-x-y),求2x+3y-m=?

Answer 1

√（x-2m-y）+√(x-4) =√(x+y-6)+√(6-x-y)

x-2m-y≥0

x-4≥0

x+y-6≥0

6-x-y≥0

x=4.y=2,m=1

2x+3y-m=13