六年级简便运算17/9÷[(4/9+1/2)×9/17]= 1又2/3×1又2/5×1又2/7×1又2/9×1又2/11

4个回答

  • 17/9÷[(4/9+1/2)×9/17]

    =17/9÷(17/18*9/17)

    =(17/9)*2

    =34/9

    1又2/3×1又2/5×1又2/7×1又2/9×1又2/11×…×1又2/199

    =5/3*7/5*9/7*.199/197*201/199

    =201/3

    =67

    (1+1/3+1/5+1/10+1/15+1/30)÷(1/2+1/4+1/6+1/12+1/20+1/60)

    =[(30+10+6+3+2+1)/30]÷[(30+15+10+5+3+1)/60]

    =(52/30)*(60/64)

    =13/8

    [17.1-17.2÷(3.1-0.7)]×0.6

    =(17.1-17.2÷2.4)*0.6

    =17.1*0.6-17.2/2.4*0.6

    =10.26-4.3

    =5.94

    (2又2/9×4/5+2又2/9×6.2-5.8×2又2/9-1/5÷9/20)×9/20

    =20/9*(0.8+6.2-5.8-0.2)*9/20

    =0.8+6.2-5.8-0.2

    =7-6

    =1

    2009÷2009又2009/2010+1/2011

    =2009÷[2009*(1+1/2010)]+1/2011

    =1÷(2011/2010)+1/2011

    =2010/2011+1/2011

    =1