首先 (a^2+4b^2)/4ab=1
[a^2+(2b)^2]/4ab=1
a^2+(2b)^2=4ab
a^2+(2b)^2-4ab=0
(a-2b)^2=0
a-2b=0
然后把a-2b=0带入2004-[73(a-2b)/2004]^2,得:
2004-(73×0/2004)^2
=2004-0
=2004
首先 (a^2+4b^2)/4ab=1
[a^2+(2b)^2]/4ab=1
a^2+(2b)^2=4ab
a^2+(2b)^2-4ab=0
(a-2b)^2=0
a-2b=0
然后把a-2b=0带入2004-[73(a-2b)/2004]^2,得:
2004-(73×0/2004)^2
=2004-0
=2004