有题意得：x≠14,2,6
log2[(x-14)(x-2)]=3+log2(6-x)
=>log2[(x-14)(x-2)]-log2(6-x)=3
=>[(x-14)(x-2)]/(6-x)=2^3
=>(x^2-16x+28)/(6-x)=8
=>x^2-16x+28=48-8x
=>x^2-8x-20=0
=>x=10或x=2(舍去)
log2[(x-14)(x-2)]=3+log2(6-x).求x?.
1个回答
相关问题
-
解方程log2(x+14)-log2(x+6)=3-log2(x+2)
-
log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+lo
-
若x满足2(log1/2 x)^2-14log4 x+3
-
2 log(3x)= log 4 +log(6-x)怎么求...急
-
log2(x^2-3x)=log二分之一（x^2-x+6)
-
求值域（1）y=log2(x) y=log2(2-x)^2 (3)y=log2(x^2-4x+6)（4）y=log1/2
-
log4(log2^x)=log2(log4^x)求log2^x
-
求方程log2 (x+1)+log2 x=log2 6的解.
-
已知x满足不等式2(log2^x)^2-7log2^x+3≤0,求f(x)=log2^(x/2) X log2^(x/4
-
Log0.5x(x(2))-14log16x(x(3))+40log4x(1x )=0