将a²+b²=6ab,代人,得,
(b-a分之a+b)²
=(a²+2ab+b²)/(a²-2ab+b²)
=(6ab+2ab)/(6ab-2ab)
=8ab/4ab
=2
因为a>b>0,
所以a-b>0,(b+a)/(b-a)>0
所以(b+a)/(b-a)=√2
将a²+b²=6ab,代人,得,
(b-a分之a+b)²
=(a²+2ab+b²)/(a²-2ab+b²)
=(6ab+2ab)/(6ab-2ab)
=8ab/4ab
=2
因为a>b>0,
所以a-b>0,(b+a)/(b-a)>0
所以(b+a)/(b-a)=√2