x²(3x+2y)²-y²(2x+3y)²
=[x(3x+2y)-y(2x+3y)][x(3x+2y)+y(2x+3y)]
=(3x²+2xy-2xy-3y²)(3x²+2xy+2xy+3y²)
=(3x²-3y²)(3x²+4xy+3y²)
=3(x-y)(x+y)(3x²+4xy+3y²0
分解因式请详解分解因式x^2(3x+2y)^2-y^2(2x+3y)^2
x²(3x+2y)²-y²(2x+3y)²
=[x(3x+2y)-y(2x+3y)][x(3x+2y)+y(2x+3y)]
=(3x²+2xy-2xy-3y²)(3x²+2xy+2xy+3y²)
=(3x²-3y²)(3x²+4xy+3y²)
=3(x-y)(x+y)(3x²+4xy+3y²0