4x+3y=6,2x+y-4=0
3个回答
4x+3y=6.(1)
2x+y-4=0.(2)
由(2)得
y=4-2x
代入(1)得
4x+12-6x=6
2x=6
x=3
则
y=4-2x=4-6=-2
解得
x=3
y=-2
相关问题
x∧6-4x∧4y∧2+6x∧3y∧3-4x∧2y∧4+y∧6因式分解
解方程2(0.3X+4)-5(0.2x-7)=9 2(3y-4)+7(4-y)=4y 4(15-2x)-6x=16x-6
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^
3x²-6x+4=0, 2x²+1=3x, y²-4√3 y+12=0, (x-3)(2x
- {5x-2y=3{x+6y=7- {x+2y=0{3x+4y-6=0- {x-y=5{2x=15-3y- {3x-2
解方程0.3x+0.4y=4,0.3x+2=0.6y
{0.6x-0.4y=1.1,0.2x-0.4y=2.3;
已知4x-3y-6z=0,2x+4y-14z=0,求2x²+3y²+6z²/x²
①﹙2x+5﹚/﹙3x-6﹚+﹙4-5x﹚/﹙2x-4﹚=0②若2x²-3xy+y²=0求x/y+y
2x-4的绝对值+(3y+6)*(3y+6)=0 则3x-4y+1