已知3x-2y-5z=0,x+2y-7z=0,xyz≠0,求(x^2-2y^2+z^2)/yz的值.
1个回答
3x-2y-5z=0,x+2y-7z=0
解得到x=3z,y=2z
x^2-2y^2+z^2/yz
=(9z^2-8z^2+z^2)/2z^2
=1
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