Question

解下列方程组 x^2+2xy+y^2=25 (x-y)^2-3x+3y+2=0

Answer 1

(x+y)^2=25,则有x+y=正负5

(x-y)^2-3(x-y)+2=0,(x-y-2)(x-y-1)=0,so x-y=2 or x-y=1

有四种可能

x+y=5 x-y=2 x=7/2 y=3/2

x+y=5 x-y=1 x=3 y=2

x+y=-5 x-y=2 x=-3/2 y=-7/2

x+y=-5 x-y=1 x=-2 y=-3