因式分解a^3+3^a^2+3a+b^3+3b^2+3b+2

4个回答

  • 1.

    a^3+3a^2+3a+b^3+3b^2+3b+2

    =a^3+3a^2+3a+1+b^3+3b^2+3b+1

    =(a+1)^3+(b+1)^3

    =(a+1+b+1)[(a+1)^2-(a+1)(b+1)+(b+1)^2]

    =(a+b+2)(a^2+2a+1-ab-a-b-1+b^2+2b+1)

    =(a+b+2)(a^2+b^2-ab+a+b+1)

    2.

    a^4-b^4+c^4-d^4-2(a^2c^2-b^2d^2)+4ac(b^2+d^2)-4bd(a^2+c^2)

    =a^4+2a^2c^2+c^4-4bd(a^2+c^2)+4b^2d^2-b^4-2b^2d^2-d^4+4ac(b^2+d^2)-4a^2c^2

    =(a^2+c^2)^2-4bd(a^2+c^2)+(2bd)^2-[(b^2+d^2)^2-4ac(b^2+d^2)+(2ac)^2]

    =[(a^2+c^2)-2bd]^2-[(b^2+d^2)-2ac]^2

    [平方差公式]

    =[(a^2+c^2-2bd)+(b^2+d^2-2ac)][(a^2+c^2-2bd)-(b^2+d^2-2ac)]

    =(a^2-2ac+c^2+b^2+d^2-2bd)(a^2+2ac+c^2-b^2-d^2-2bd)

    =(a^2-2ac+c^2+b^2+d^2-2bd)[(a+c)^2-(b+d)^2]

    =(a^2-2ac+c^2+b^2+d^2-2bd)(a+c+b+d)(a+c-b-d)

    3.

    x^3+y^3+3xy-1

    =(x+y)^3-3x^2y-3xy^2+3xy-1

    =(x+y)^3-3xy(x+y-1)-1

    =[(x+y)-1][(x+y)^2+(x+y)+1]-3xy(x+y-1)

    =(x+y-1)(x^2+2xy+y^2+x+y+1-3xy)

    =(x+y-1)(x^2-xy+y^2+x+y+1)

    4.

    (x+y+z)3+(3x-2y-3z)3-(4x-y-2z)3

    =(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2]-(4x-y-2z)3

    =(4x-y-2z)[(x+y+z)^2-2(x+y+z)(3x-2y-3z)+(3x-2y-3z)^2-(4x-y-2z)^2]

    =(4x-y-2z)[(x+y+z)((x+y+z)-(3x-2y-3z))+((3x-2y-3z)-(4x-y-2z))((3x-2y-3z)+(4x-y-2z))]

    =(4x-y-2z)[(x+y+z)(-2x+3y+4z)+(-x-y-z)(7x-3y-5z)]

    =(4x-y-2z)(x+y+z)[(-2x+3y+4z)-(7x-3y-5z)]

    =(4x-y-2z)(x+y+z)(-9x+6y+9z)

    =3(4x-y-2z)(x+y+z)(-3x+2y+3z)

    太复杂了,应该加分啊.