[4(x-2)²+12(x+2)(x-2)-8(x-1)² * (x-2)]÷[4(x-2)]
=4(x-2)[(x-2)+3(x+2)-2(x-1)²]÷[4(x-2)]
=x-2+3x+6-2(x-1)²
=4x+4-2(x²-2x+1)
=4x+4-2x²+4x-2
=-2x²+8x+2
[4(x-2)²+12(x+2)(x-2)-8(x-1)² * (x-2)]÷[4(x-2)]
=4(x-2)[(x-2)+3(x+2)-2(x-1)²]÷[4(x-2)]
=x-2+3x+6-2(x-1)²
=4x+4-2(x²-2x+1)
=4x+4-2x²+4x-2
=-2x²+8x+2