集合A={x|x²-4x≦0,x∈Z}中不等式:x²-4x≦0化为:x(x-4)≦0
解得:0≦x≦4
又x∈Z,那么:A={0,1,2,3,4}
已知B={y|y=log2(x+1),x∈A},所以:
当x=0时,y=log2 1=0;当x=1时,y=log2 2=1;
当x=2时,y=log2 3;当x=3时,y=log2 4=2;
当x=4时,y=log2 5
即有:B={ 0,1,2,(log2 3),(log2 5)}
所以:A∩B={0,1,2}
集合A={x|x²-4x≦0,x∈Z}中不等式:x²-4x≦0化为:x(x-4)≦0
解得:0≦x≦4
又x∈Z,那么:A={0,1,2,3,4}
已知B={y|y=log2(x+1),x∈A},所以:
当x=0时,y=log2 1=0;当x=1时,y=log2 2=1;
当x=2时,y=log2 3;当x=3时,y=log2 4=2;
当x=4时,y=log2 5
即有:B={ 0,1,2,(log2 3),(log2 5)}
所以:A∩B={0,1,2}