求和cscA secA cotA有关的公式

1个回答

  • 两角和公式

    sin(A+B) = sinAcosB+cosAsinB

    sin(A-B) = sinAcosB-cosAsinB

    cos(A+B) = cosAcosB-sinAsinB

    cos(A-B) = cosAcosB+sinAsinB

    tan(A+B) = (tanA+tanB)/(1-tanAtanB)

    tan(A-B) = (tanA-tanB)/(1+tanAtanB)

    cot(A+B) = (cotAcotB-1)/(cotB+cotA)

    cot(A-B) = (cotAcotB+1)/(cotB-cotA)

    倍角公式

    Sin2A=2SinA•CosA

    Cos2A=CosA^2-SinA^2=1-2SinA^2=2CosA^2-1

    tan2A=2tanA/1-tanA^2

    和差化积

    sin(a)+sin(b) = 2sin[(a+b)/2]cos[(a-b)/2]

    sin(a)-sin(b) = 2cos[(a+b)/2]sin[(a-b)/2]

    cos(a)+cos(b) = 2cos[(a+b)/2]cos[(a-b)/2]

    cos(a)-cos(b) = -2sin[(a+b)/2]sin[(a-b)/2]

    tanA+tanB=sin(A+B)/cosAcosB

    积化和差

    sin(a)sin(b) = -1/2*[cos(a+b)-cos(a-b)]

    cos(a)cos(b) = 1/2*[cos(a+b)+cos(a-b)]

    sin(a)cos(b) = 1/2*[sin(a+b)+sin(a-b)]

    cos(a)sin(b) = 1/2*[sin(a+b)-sin(a-b

    诱导公式

    sin(-a) = -sin(a)

    cos(-a) = cos(a)

    sin(π/2-a) = cos(a)

    cos(π/2-a) = sin(a)

    sin(π/2+a) = cos(a)

    cos(π/2+a) = -sin(a)

    sin(π-a) = sin(a)

    cos(π-a) = -cos(a)

    sin(π+a) = -sin(a)

    cos(π+a) = -cos(a)

    tanA= sinA/cosA

    tan(π/2+α)=-cotα

    tan(π/2-α)=cotα

    其他非重点三角函数

    csc(a) = 1/sin(a)

    sec(a) = 1/cos(a)

    这都是比较常用的!

    天天开心!

    sin3a=sin2acosa+cos2asina

    =2sinacosacosa+[1-2(sina)^2]sina

    =-4(sina)^3+3sina.

    cos3a=cos2acosa-sin2asina

    =[2(cosa)^2-1]cosa-2sinacosasina

    =4(cosa)^3-3cosa.

    tan3a=(tan2a+tana)/(1-tan2atana)

    =[2tana/(1-(tana)^2)+tana]/[1-29tana)^2/(1-(tana)^2)]

    =[3tana-(tana)^3]/[1-3(tana)^2].