Question

如图四边形ABCD,CDFE,EFGH,都是正方形则角AFB与角AHB的度数之和为多少?

Answer 1

AFB=a,AHB=b

tga=1/2 tgb=1/3

tg(a+b)=(tga+tgb)/(1-tga*tgb)=(1/2+1/3)/(1-1/2*1/3)=1

a+b=45