[(2009-x)-(2007-x)]^2
=(2009-x)^2+(2007-x)^2-2(2009-x)(2007-x)
=(2009-x)^2+(2007-x)^2-2*2008
=2^2=4
所以:(2009-x)^2+(2007-x)^2
=4+2*2008
=4020
[(2009-x)-(2007-x)]^2
=(2009-x)^2+(2007-x)^2-2(2009-x)(2007-x)
=(2009-x)^2+(2007-x)^2-2*2008
=2^2=4
所以:(2009-x)^2+(2007-x)^2
=4+2*2008
=4020