Question

求多项式3x^2y-4xy^2-3+5x^2y+2xy^2+5的值,期中x=-1,y=2

Answer 1

3x^2y-4xy^2-3+5x^2y+2xy^2+5

=8x^y-2xy^2+2

=8x(-1)²x2-2x(-1)x2²+2

=16+8+2

=26

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