Question

一道有关物质的量的高一化学题中和10%的硫酸溶液49g,需要加入NaOH固体多少摩尔?反应后生成的盐的质量百分比浓度是多

Answer 1

设需NaOH:xmol,反应后生成的Na2SO4:ymol

(1)H2SO4 + 2NaOH = Na2SO4 + 2H2O

..1.2.1

49*10%/98.x.y

x=0.1mol;

m(NaOH)=40*0.1=4(g)

(2)y=0.05mol;

m(Na2SO4)=142*0.05=7.1(g)

w(Na2SO4)=[7.1/(49+4)]*100%=13.4%