4x^4y²-5x²y²-9y²用十字相乘法分解因式

1个回答

  • 1.4x^4y²-5x²y²-9y²

    =y²(4x^4-5x²-9)

    =y²(4x²-9)(x²+1)

    =y²(x²+1)(2x+3)(2x-3)

    2.2(a-b)²-(a-b)-3

    =[2(a-b)-3][(a-b)+1]

    =(2a-2b-3)(a-b+1)

    3.4(2x+y)²-8(2x+y)+3

    =[2(2x+y)-1][2(2x+y)-3]

    =(4x+2y-1)(4x+2y-3)

    ]

    4.7x^4+5x²y²-2y^4

    =(x²+y²)(7x²-2y²)

    5.5x³y-7x²y-6xy

    =xy(5x²-7x-6)

    =xy(5x+3)(x-2)