1、A,B,C为三角形内角,已知1+cos2A-cos2B-cos2C=2sinBsinC,求角A1+cos2A-cos2B-cos2C=2sinBsinC2cos²A-1-2cos²B+1+2sin²C=2sinBsinCcos²A-cos²B+sin² (A+B)=sinBsinCcos²A-cos&s...
1、A,B,C为三角形内角,已知1+cos2A-cos2B-cos2C=2sinBsinC,求角A1+cos2A-cos2B-cos2C=2sinBsinC2cos²A-1-2cos²B+1+2sin²C=2sinBsinCcos²A-cos²B+sin² (A+B)=sinBsinCcos²A-cos&s...