Question

解2log2^(x-5)=log2^(x-1)+1

Answer 1

2log2^(x-5)=log2^(x-1)+1

log2^(x-5)^2=log2^[2*(x-1)]

(x-5)^2=2(x-1)

x^2-12x+27=0

(x-3)(x-9)=0

x=3,x=9

代入检验

x=3使得log2^(x-5)无意义

所以x=9