由题意,得:[Ra×U/(R+Ra)]:[Rb×U/(R+Rb)]=2:7;将Rb=7Ra代入上式,解得:R=5Ra.
(1)p在a点和b点时的电流之比为:Ia:Ib=[U/(5Ra+Ra)]:[U/(5Ra+7Ra)]=2:1.
(2)∵R=5Ra,滑动变阻器接入电路最大阻值为Rb=7Ra,∴R:Rb=5Ra:7Ra=5:7.
由题意,得:[Ra×U/(R+Ra)]:[Rb×U/(R+Rb)]=2:7;将Rb=7Ra代入上式,解得:R=5Ra.
(1)p在a点和b点时的电流之比为:Ia:Ib=[U/(5Ra+Ra)]:[U/(5Ra+7Ra)]=2:1.
(2)∵R=5Ra,滑动变阻器接入电路最大阻值为Rb=7Ra,∴R:Rb=5Ra:7Ra=5:7.