求极限急:求极限lim x→无穷 (x³-2x-5)/(7x³+5x²+6x+8)
1个回答
limx->∞(x³-2x-5)/(7x³+5x²+6x+8)
=limx->∞x³(1-2/x^2-5/x^3)/x³(7+5/x+6/x^2+8/x^3)
=1/7
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